Python：每日一题 95（答题领鱼币）

guoqing3511

print("1fishc|\n2fishc\n3fishc\n4fishc\n5little turtle\n")

5jj

不知道

AKA2pac

def addhead(list1):
    count = 0
    for i in range(0,len(list1)):
        for j in range(i + 1,len(list1)):
            if list1[j] == list1[i]:
                count += 1
        print('(' + str(count) + ')' + list1[i])
        count = 0


list2 = ['FishC', 'FishC', 'FishC', 'FishC', 'Little turtle', 'Little turtle', 'Python', 'FishC']
addhead(list2)

741712547

1. a = """FishC
   
2. FishC
   
3. FishC
   
4. FishC
   
5. Little turtle
   
6. Little turtle
   
7. Python
   
8. FishC"""
   
9. list1 = a.split('\n')
   
10. list3 = list1.copy()
    
11. list3.reverse()
    
12. list4 = [0]
    
13. list5 = []
    
14. 
    
15. changdu = len(list3)
    
16. for index in range(1,changdu):
    
17.     if list3[index-1] == list3[index]:
    
18.         list4.append(1)
    
19.         list4[index] = (list4[index]+list4[index-1])
    
20.     else:
    
21.         list4.append(0)
    
22. for index in range(changdu):
    
23.     list5.append('('+str(list4[index])+')'+list3[index])
    
24. list5.reverse()
    
25. for char in list5:
    
26.     print(char)

复制代码

思路是，用两个列表拼接。倒是实现了，但是有点笨办法。

dnwz

1. strVal = """
   
2.     FishC
   
3.     FishC
   
4.     FishC
   
5.     FishC
   
6.     Little turtle
   
7.     Little turtle
   
8.     Python
   
9.     FishC
   
10. """
    
11. newStrVal = strVal.split('\n')
    
12. strlist = [value.strip() for value in newStrVal if value.strip() is not '']
    
13. length = len(strlist)
    
14. 
    
15. for i in range(length):
    
16. &nbsp; &nbsp; j = i+1 if i+1<length else length
    
17. &nbsp; &nbsp; n = 0
    
18. &nbsp; &nbsp; for j in range(j,length):
    
19. &nbsp; &nbsp;&nbsp; &nbsp;&nbsp;&nbsp;if strlist[i] == strlist[j]:
    
20. &nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;n += 1
    
21. &nbsp; &nbsp;&nbsp; &nbsp;&nbsp;&nbsp;else:
    
22. &nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;&nbsp; &nbsp;break
    
23. &nbsp; &nbsp; print("(%d)%s" % (n,strlist[i]))

复制代码

dnwz

lihuayuan

不知道哦

根号三.5

s1='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
s1=s1.split('\n')
num=len(s1)
for i in range(num):
    count=0
    for j in range(i+1,num):
        if s1[i]==s1[j]:
            count+=1
        else:
            break
    s1[i]='('+str(count)+')'+s1[i]
print('\n'.join(s1))

Linco

1. text = """FishC
   
2. FishC
   
3. FishC
   
4. FishC
   
5. Little turtle
   
6. Little turtle
   
7. Python
   
8. FishC"""
   
9. print(text.split('\n'))
   
10. out = {}
    
11. o = []
    
12. for line in text.split('\n'):
    
13.     prev = out.get(line, 0)
    
14.     if prev == 0 and len(out) != 0:
    
15.         k, v = out.popitem()
    
16.         for n in reversed(range(0, v)):
    
17.             o.append('(%s)%s' % (n, k))
    
18.     out[line] = out.get(line, 0) + 1
    
19. print('\n'.join(o))

复制代码

liuwenqi

content ='''FishC
FishC
FishC
FishC
Little turtle
Little turtle
Python
FishC'''
content = content.split('\n')
for num,each in enumerate(content):
    for i in range(num, len(content)):
        if i == False:
            print(0, each)
        elif each != content[i]:
            print(i-num-1, each)
            break
   

fangchuhao

问问

upc-xiaoxiao

学习一下

咖喱168

不会

扫描仪

不知道啊

timeislife

看看

shigure_takimi

1. a ='''FishC
   
2. FishC
   
3. FishC
   
4. FishC
   
5. Little turtle
   
6. Little turtle
   
7. Python
   
8. FishC'''
   
9. 
   
10. def func(string):
    
11.     b = string.split('\n')
    
12.     counts = [] # 存放每个字符串后面跟着的相同字符串的个数
    
13.     for i in range(len(b)):
    
14.         count_i = 0
    
15.         for j in range(i+1,len(b)):
    
16.             if b[i] == b[j]:
    
17.                 count_i += 1
    
18.             else:
    
19.                 break
    
20.         counts.append(count_i)
    
21.     for count_i, subString in zip(counts, b):
    
22.         print("({0}){1}".format(count_i,subString))
    
23. func(a)
    
24. 
    
25. 
    
26. ##    >>>
    
27. ##    (3)FishC
    
28. ##    (2)FishC
    
29. ##    (1)FishC
    
30. ##    (0)FishC
    
31. ##    (1)Little turtle
    
32. ##    (0)Little turtle
    
33. ##    (0)Python
    
34. ##    (0)FishC
    
35. ##        
    
36. ##    完美符合预期。

复制代码

yjsx86

1. s = '''FishC
   
2. FishC
   
3. FishC
   
4. FishC
   
5. Little turtle
   
6. Little turtle
   
7. Python
   
8. FishC'''
   
9. [print('(%d)%s' % (i,k)) for k,v in it.groupby(s.split('\n')) for i in range(len(list(v)))[::-1]]

复制代码

新手潘包邮

jerryxjr1220 发表于 2017-9-8 18:12

您好，大佬能不能分享下学习经验

新手潘包邮

import itertools
def fun(string):
    print(string)
    string = string.split("\n")
    string.reverse()
    j = 0
    string[0] = "(%s)"%j + string[0]
    for i in range(1, len(string)):
        if string[i] == string[i-1][3:]:
            j += 1
            string[i] = "(%s)"%j + string[i]
        else:
            j = 0
            string[i] = "(%s)"%j + string[i]
    print(string)
    string.reverse()
    a = itertools.groupby(string)
    for i, j in a:
        print(i)
    #print(a)
    pass
fun("FishC\nFishC\nFishC\nLittle turtle\nLittle turtle\nFishC")

Geoffreylee

1. import itertools
   
2. 
   
3. def f_95(string: str):
   
4.     for key, group in itertools.groupby(string.split('\n')):
   
5.         lst = list(group)
   
6.         for index, value in enumerate(lst):
   
7.             print('({}) {}'.format(len(lst)-index-1, value))

复制代码