Python：每日一题 11

renze

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aixuexi82

1. X = [[12,7,3],
   
2.     [4,5,6],
   
3.     [7,8,9]]
   
4. 
   
5. Y = [[5,8,1],
   
6.     [6,7,3],
   
7.     [4,5,9]]
   
8. 
   
9. Z = X[:]
   
10. for i in range(3):
    
11.     for j in range(3):
    
12.         Z[i][j]=X[i][j]+Y[i][j]
    
13. print(Z)

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石小龙

1. import numpy as n
   
2. x = [[12,7,3],
   
3.     [4,5,6],
   
4.     [7,8,9]]
   
5. y = [[5,8,1],
   
6.     [6,7,3],
   
7.     [4,5,9]]
   
8. a = n.array(x)
   
9. b = n.array(y)
   
10. c = a + b
    
11. print(c)

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编程新血

随便写的，看看答案。

x = [[12,7,3],[4,5,6],[7,8,9]]
y = [[5,8,1],[6,7,3],[4,5,9]]
xy=x[:]
for i in range(len(y)):
    for i2 in range(len(y[i])):
        xy[i][i2]+=y[i][i2]
print(xy)

achencan

技术不够，用简单知识写的，写得很多---------------

1. def splist(l,s):
   
2.     return [l[i:i+s] for i in range(len(l)) if i%s==0]
   
3. X = [[12,7,3],
   
4.     [4,5,6],
   
5.     [7,8,9]]
   
6. 
   
7. Y = [[5,8,1],
   
8.     [6,7,3],
   
9.     [4,5,9]]
   
10. list1 = []
    
11. list2 = []
    
12. list3 = []
    
13. for j in range(0,3):
    
14.     for x in X[j]:
    
15.         list1.append(x)
    
16.     for y in Y[j]:
    
17.         list2.append(y)
    
18. for i in range(0,9):
    
19.     data = list1[i] + list2[i]
    
20.     list3.append(data)
    
21. list4 = splist(list3,3)
    
22. for k in range(3):
    
23.     print list4[k]

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david_van

1. #两个3行3列的矩阵，实现对应位置的数据相加，并返回新的矩阵
   
2. X = [[12,7,3],[4,5,6],[7,8,9]]
   
3. Y = [[5,8,1],[6,7,3],[4,5,9]]
   
4. result = []
   
5. for i in range(len(X)):
   
6.         temp = []
   
7.         for j in range(len(X[i])):
   
8.                 temp.append(X[i][j]+Y[i][j])
   
9.         result.append(temp)
   
10. print(result)
    

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感觉对于一个X和Y一样的矩阵可行

shigure_takimi

1. X = [[12,7,3],
   
2.     [4,5,6],
   
3.     [7,8,9]]
   
4. 
   
5. Y = [[5,8,1],
   
6.     [6,7,3],
   
7.     [4,5,9]]
   
8. 
   
9. 
   
10. 
    
11. def addXY(x, y):
    
12.     Z = [list(zip(X[i],Y[i])) for i in range(len(X))]
    
13.     for i in range(len(X)):
    
14.         for j in range(len(X[0])):
    
15.             Z[i][j] = sum(Z[i][j])
    
16.     return Z
    
17. 
    
18. print(addXY(X,Y))
    
19. 
    
20. ##  输出： [[17, 15, 4], [10, 12, 9], [11, 13, 18]]

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yjsx86

1. X = [[12,7,3],
   
2.     [4,5,6],
   
3.     [7,8,9]]
   
4. 
   
5. Y = [[5,8,1],
   
6.     [6,7,3],
   
7.     [4,5,9]]
   
8. 
   
9. rs = [[sum(j) for j in zip(i[0],i[1])] for i in zip(X, Y)]
   
10. print(rs)

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# result
[[17, 15, 4], [10, 12, 9], [11, 13, 18]]

壁垒来了

x= [[12,7,3],
    [4,5,6],
    [7,8,9]]
y= [[5,8,1],
    [6,7,3],
    [4,5,9]]
a=[]
for j in range(3):
    a.append([x[j][i]+y[j][i]for i in range(3)])
print(a)

1141429506

1. from numpy import *
   
2. b = array([[12, 7, 3], [4, 5, 6], [7, 8, 9]])
   
3. a = array([[5, 8, 1], [6, 7, 3], [4, 5, 9]])
   
4. list1=[]
   
5. list2=[]
   
6. for i in range(3):
   
7.     for j in range(3):
   
8.         m=b[i,j]+a[i,j]
   
9.         list1.append(m)
   
10.     list2.append(list1)
    
11.     list1=[]
    
12. print(array(list2))

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请求回答

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会飞的狼666

看一波

TheKernel

哈哈哈

回不去的鱼

学习！！

z1446773686

x = [[12,7,3],
    [4,5,6],
    [7,8,9]]

y = [[5,8,1],
    [6,7,3],
    [4,5,9]]

list1 = []
if len(x) == len(y):
                for i in range(len(x)):
                                list1.append([])
                                for j in range(len(x[i])):
                                                list1[i].append(x[i][j] + y[i][j])
print(list1)

借鉴一位鱼油的

ultraji

1. X = [[12,7,3],
   
2.     [4,5,6],
   
3.     [7,8,9]]
   
4. Y = [[5,8,1],
   
5.     [6,7,3],
   
6.     [4,5,9]]
   
7. for i in range(3):
   
8.     for j in range(3):
   
9.         X[i][j] += Y[i][j]
   
10. print(X)

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sunflower-柠檬

两个想加后不知道怎么打印出来

不失微笑

h

victor.xu

谢谢

lchelement

X = [[12,7,3],
    [4,5,6],
    [7,8,9]]

Y = [[5,8,1],
    [6,7,3],
    [4,5,9]]

Z = [[0,0,0],
     [0,0,0],
     [0,0,0]]

for i in range(3):
    for j in range(3):
        Z[i][j]=X[i][j]+Y[i][j]
print(Z)